Skip to main content

Capgemini Sample Dimensions Based Questions

Question 1
A manufacturer reduces the size of his machine of Material1 from 30" to 28" and that of Material2 from 24" to 23". He normally spends Rs.1440 for Material1 and Material2. 3/4th of the amount spent would be for Material1. How much will he save under the size of new size (Assuming that the costs incurred by the machines are directly proportional to their sizes)?
a)Rs.85 b)Rs.87 c)Rs.86 d)Rs.88
Answer : b)Rs.87
The manufacturer totally spends Rs.1440 for both material 1 and 2.
Out of this 3/4th is entirely for Material1.
Amount spent on Material1 = 1440 x 3/4 = Rs.1080
i.e, he spent Rs.1080 for Material1 of 30" and he reduces 2".
 Size  Amount
 30"  Rs.1080
 2"    ?
Amount saved on Material1 = 1080 x 2/30 = Rs.72
Amount spent on Material2 = total amount - amount for Material1 = 1440 - 1080 = Rs.360.
i.e., he spent Rs.360 for Material2 of 24" and he reduces 1".
 Size  Amount
 24"  Rs.360
 1"    ?
Amount saved on Material2 = 360 x 1/24 = Rs.15
Therefore total amount saved after size reduction = 72 + 15 = Rs.87
Question 2
The dimensions of a certain machine are X" x Y" x Z". If the average of its dimensions equals 680" and none of the dimensions is less than 640", what is the greatest possible length of one of the dimensions?
a)760" b)800" c)720" d)745"
Answer : a) 760"
Given (X+Y+Z)/3 = 680".
Therefore the total length of the dimensions is X + Y + Z = 3 x 680 = 2040.
Let us assume Z is the dimension with greatest possible length.
From above equation, Z = 2040 - X - Y ...(1)
Based on eq (1), for Z to be of maximum value, X and Y should be as low as possible. Since it is given that none of the dimensions is lesser than 640", the lowermost value that X and Y can get is 640".
Substituting X = Y = 640" in eq (1), we get,
Z = 2040 - 640 -640 = 760".
Question 3
What will be the ratio of the shortest side of new dimensions to the greatest side of the old dimensions if the size of a certain machine is increased proportionally until the sum of its dimensions equals 800" and the dimensions of old size are 130" x 60" x 360" ?.
a)1:2 b)3:5 c)5:18 d)18:3
Answer : c) 5:18
From the given data, we have
The dimensions of the machine before size increment = 130" x 70" x 360".
Sum of the dimensions = 130+70+360 = 560"
Note that the greatest side = 360" & smallest side = 70". ...(A)
It is given that the sum of the dimensions of new size = 800"
Since dimensions are increased proportionately, the smallest side of the old dimensions before increment will be the smallest side of new dimension after size increment.
 Sum  Side
 560"   70"
 800"    ?
Smallest side will be increased to 800 x 70 / 560 = 100"
i.e., the smallest side of the new dimensions is 100". 
We have already found that the the greatest side of old dimensions is 360".
Required Ratio = Smallest side of the New Dimensions : Greatest side of the Old 
= 100 : 360 = 5 : 18
Hence the answer is 5 : 18.


Popular posts from this blog


Agricultural Research Service

Eligibility Test/ Senior Research Fellowship Examination 

The Agricultural Scientists Recruitment Board (ASRB)
 holds a Competitive Examination for recruiting Scientists of the ARS in the pay scale of Rs. 8,000-13,500 in the ICAR Institutes, combined with National Eligibility Test (NET) for recruitment of Lecturers and Assistant Professors by the State Agricultural Universities (SAUS) and for award of ICAR Senior Research Fellowships.

The selected candidates for Agricultural Research Service must serve in the institutes to which they are posted until they find appointment for higher positions through selection at other institutes.

(i) Candidates successful in ARS are appointed as Scientists in the Indian Council of Agricultural Research in the pay scale of Rs. 8,000-13,500.

(ii) Candidates clearing the National Eligibility Test are recommended to various State Agricultural Universities who will consider them for appointment as Lecturers or Assistant Pro…


The Union Public Service Commission (U.P.S.C.) conducts Civil Services' Examination once a year in two stages. The Preliminary Examination (Objective Type) for selection of candidates for the Main Examination is held in the month of May.

The Civil Services Main Examination
 is held in the months of October/November. Blank application forms and other particulars are published in the Employment News, generally in the month of December.

The last date for the submission of applications to the Secretary, Union Public Service Commission, Dholpur House, Shahjahan Road, NewDelhi-11001 1 is usually the last week of January of the year of examination.

The Combined Civil Services Examination is conducted for Recruitment to the following Services/Posts:

1. Indian Administrative Service.
2. Indian Foreign Service.
3. Indian Police Service.
4. Indian P & T Accounts & Finance Service, Group 'A'.
5. Indian Audit and Accounts Service, Group 'A'.
6. Indian Customs and Central Excise S…

Aptitude Test Practice Questions - With Answers

Question 1. Which of the following is least like the others?
A.    cube
B.    sphere
C.    pyramid
D.    circle

D (because the circle is the only two-dimensional figure)

Question 2. Consider a language which uses the following set of characters:
Small set: { a b c }
Large set: { A B C }
Punctuation set: { x y }
This language must follow the following rules:
  1.    A punctuation character must end all series.
  2.    A series can have up to but no more than 4          characters,including punctuation characters.

Does the following series follow all the rules of the language defined above?
  A.    Yes
  B.    No

A (the series has only four characters and ends in a punctuation character)

Question 3. Consider the following flow chart for a customer:

The person in No.1 is:
    A.   Married, with children
    B.   Married, with at least one son
    C.   Unmarried, with at least one daughter
    D.   Unmarried, with at least one son
    E.   Unmarried, with no children