Below are three questions on numbers on concepts dealing with odd and even and a new class called "even-odd" numbers.

If n is an even-odd number then which of the following must be false?

(A number is called "even-odd" if it is halfway between an even integer and an odd integer.)

a) n/2 is not an integer

b)(2n)2 is an integer

c)4n is an odd integer

d)none of these

Solution:

A number is called "even-odd" if it is halfway between an even integer and an odd integer. For example, consider an even integer 10 and an odd integer -5. Number halfway between them will be (10 - (-5)) / 2 = 7.5. Here 7.5 is an "even-odd" number.

i.e., an even-odd number will be in the form x + 1/2 = x.5 where x is any integer.

Let us see with each option:

Consider option a :

Since n is a fraction number then n/2 is also a fraction.

i.e., n/2 is not an integer.

Hence option a is true.

Consider option b :

(2n)2 = 4n2

since n…

**Question 1**If n is an even-odd number then which of the following must be false?

(A number is called "even-odd" if it is halfway between an even integer and an odd integer.)

a) n/2 is not an integer

b)(2n)2 is an integer

c)4n is an odd integer

d)none of these

**Answer :**c)4n is an odd integerSolution:

A number is called "even-odd" if it is halfway between an even integer and an odd integer. For example, consider an even integer 10 and an odd integer -5. Number halfway between them will be (10 - (-5)) / 2 = 7.5. Here 7.5 is an "even-odd" number.

i.e., an even-odd number will be in the form x + 1/2 = x.5 where x is any integer.

Let us see with each option:

Consider option a :

Since n is a fraction number then n/2 is also a fraction.

i.e., n/2 is not an integer.

Hence option a is true.

Consider option b :

(2n)2 = 4n2

since n…