A Guide to make you Prepare for Placements, Aptitude Tests, Interviews, projects...

A Guide to make you Prepare for Placements, Aptitude Tests, Interviews, projects...

Showing posts from January, 2013

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Four concentric circles are drawn with the radii at interval of X units. If the radius of inner circle is X units then the ratio of the area between the 4th and 3rd circles to the area between the 2nd and 1st circles is:

a)1:2 b)2:1 c)4:3 d)7:3

Solution :

Let X be the radius of inner(1st) circle.

Given that the radii of the circles are at the intervals of X units.

Then X + X = 2X, 2X + X = 3X, 3X + X = 4X are the radii of successive circles respectively.

Now, the area of first circle = pi(X)2 = pi x X2

Area of second circle = pi(2X)2 = 4 x pi x X2

Area of third circle = pi(3X)2 = 9 x pi x X2

Area of fourth circle = pi(4X)2 = 16 x pi x X2

Then, the area between 1st and 2nd circles = (4 x pi x X2) - (pi x X2) = 3piX2br />

And the area between 3rd and 4th circles = (16 x pi x X2) - (9 x pi x X2) = 7piX2

Therefore the required ratio = 7piX2 / 3piX2 = 7/3

Hence the answer is 7:3

88 and 66 are the sum and difference of the perimeter of two c…

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The State Education Board Maharashtra has declared the **10th class board exam time table 2013**
on the starting of the academic year itself. Maharashtra SSC board
exams are going to start from 2nd of march and will be end on 21st of
march as general category.

**PDF file of time table**

Students who are appearing for**Maharashtra Board 10th Examination 2013** are hereby informed to check **10th class Maharashtra board final exams time table**.

Students can see the SSC Board exams time table with date, day, paper name and timing. Secondary School Certificate (SSC) Examination March 2013 Time TablePaperDateDayTimeHindi/Marathi(First Language)02-03-2013Saturday11.00 am to 2.00pmHindi(second language)05-03-2013Tuesday11.00 am to 2.00 pmEnglish07-03-2013Thursday11.00 am to 2.00 pSanskrit/urdu09-03-2013Saturday11.00 am to 2.00 pmScience12-03-2013Tuesday11.00 am to 1.30 pmAlgebra14-03-2013Thursday11.00 am to 1.30 pmGeometry16-03-2013Saturday11.00 am to 1.30 pmHistory & civics19-03-2013Tuesday11.00 am…

Students who are appearing for

Students can see the SSC Board exams time table with date, day, paper name and timing. Secondary School Certificate (SSC) Examination March 2013 Time TablePaperDateDayTimeHindi/Marathi(First Language)02-03-2013Saturday11.00 am to 2.00pmHindi(second language)05-03-2013Tuesday11.00 am to 2.00 pmEnglish07-03-2013Thursday11.00 am to 2.00 pSanskrit/urdu09-03-2013Saturday11.00 am to 2.00 pmScience12-03-2013Tuesday11.00 am to 1.30 pmAlgebra14-03-2013Thursday11.00 am to 1.30 pmGeometry16-03-2013Saturday11.00 am to 1.30 pmHistory & civics19-03-2013Tuesday11.00 am…

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a)1:2 b)2:1 c)4:3 d)7:3

Solution :

Let X be the radius of inner(1st) circle.

Given that the radii of the circles are at the intervals of X units.

Then X + X = 2X, 2X + X = 3X, 3X + X = 4X are the radii of successive circles respectively.

Now, the area of first circle = pi(X)2 = pi x X2

Area of second circle = pi(2X)2 = 4 x pi x X2

Area of third circle = pi(3X)2 = 9 x pi x X2

Area of fourth circle = pi(4X)2 = 16 x pi x X2

Then, the area between 1st and 2nd circles = (4 x pi x X2) - (pi x X2) = 3piX2br />

And the area between 3rd and 4th circles = (16 x pi x X2) - (9 x pi x X2) = 7piX2

Therefore the required ratio = 7piX2 / 3piX2 = 7/3

Hence the answer is 7:3

88 and 66 are the sum and difference of the perimeter of two co…

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